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Calculus, MET1 2019 VCAA 1b

Let  `g: R text(\ {−1}) -> R,\ \ g(x) = (sin(pi x))/(x + 1)`.

Evaluate  `g^{prime}(1)`.   (2 marks)

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`-pi/2`

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  `u = sin(pi x)` `v = x + 1`
  `u^{prime}=pi cos(pi x)` `v^{prime}=1`

 

`g^{prime}(x)` `=(vu^{prime}-uv^{prime})/v^2`
  `= ((x + 1) ⋅ pi cos(pi x)-sin (pi x))/(x + 1)^2`
`g^{prime}(1)` `= (2 pi cos(pi)-sin(pi))/2^2`
  `= (2 pi(-1)-0)/4`
  `= -pi/2`

Filed Under: Differentiation (Trig), Trig Differentiation Tagged With: Band 4, smc-736-10-sin, smc-736-50-Quotient Rule, smc-736-60-Chain Rule, smc-744-10-sin, smc-744-50-Quotient Rule, smc-744-60-Chain Rule

Calculus, MET1 2007 ADV 2ai

Let  `f(x)=(1 + tan x)^10.` Find  `f^{\prime}(x)`.   (2 marks)

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`10 sec^2 x \ (1 + tan x)^9`

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`f(x) = (1 + tan x)^10`

`f^{\prime}(x)` `= 10 (1 + tan x)^9 xx d/(dx) (tan x)`
  `= 10 sec^2 x \ (1 + tan x)^9`

Filed Under: Differentiation (Trig), Trig Differentiation Tagged With: Band 3, smc-736-30-tan, smc-736-60-Chain Rule, smc-744-30-tan, smc-744-60-Chain Rule

Calculus, MET1 SM-Bank 20

If   `f(x)= 2 sin 3x - 3 tan x`, find  `f^{prime}(0)`.   (2 marks)

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`3`

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`y` `= 2 sin 3x-3 tan x`
`(dy)/(dx)` `= 6 cos 3x-3 sec^2 x`

  
`text(When)\ \ x = 0,`

`(dy)/(dx)` `= 6 cos 0-3 sec^2 0`
  `= 6 (1)-3/(cos^2 0)`
  `= 6-3`
  `= 3`

Filed Under: Differentiation (Trig), Trig Differentiation Tagged With: Band 4, smc-736-10-sin, smc-736-30-tan, smc-736-60-Chain Rule, smc-744-10-sin, smc-744-30-tan, smc-744-60-Chain Rule

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