Ita publishes and sells calendars for $25 each. The cost of producing the calendars is $8 each plus a set up cost of $5950.
How many calendars does Ita need to sell to breakeven? (2 marks)
--- 5 WORK AREA LINES (style=lined) ---
Aussie Maths & Science Teachers: Save your time with SmarterEd
Ita publishes and sells calendars for $25 each. The cost of producing the calendars is $8 each plus a set up cost of $5950.
How many calendars does Ita need to sell to breakeven? (2 marks)
--- 5 WORK AREA LINES (style=lined) ---
`350`
`text(Let)\ \ x =\ text(number of calendars sold)`
`text(C)text(ost) = 5950 + 8x`
`text(Sales revenue) = 25x`
`text(Breakeven occurs when:)`
| `25x` | `= 5950 + 8x` |
| `17x` | `= 5950` |
| `:. x` | `= 350` |
Sue and Mikey are planning a fund-raising dance. They can hire a hall for $400 and a band for $300. Refreshments will cost them $12 per person.
--- 2 WORK AREA LINES (style=lined) ---
The graph shows planned income and costs when the ticket price is $20.
--- 1 WORK AREA LINES (style=lined) ---
--- 2 WORK AREA LINES (style=lined) ---
Sue and Mikey plan to sell 200 tickets. They want to make a profit of $1500.
--- 6 WORK AREA LINES (style=lined) ---
a. `700 + 12x`
b. `text(Approximately 90)`
c. `$500`
d. `$23`
a. `$C= 400 + 300 + (12 xx x)= 700 + 12x`
b. `text(Using the graph intersection:)`
`text(Approximately 90 people are needed to cover the costs.)`
c. `text(If 150 people attend)`
`text(Income)= 150 xx $20= $3000`
`text(C)text(osts)= 700 + (12 xx 150)= $2500`
`:.\ text(Profit)= 3000-2500= $500`
d. `text(C)text(osts when)\ x = 200:`
`C=700 + (12 xx 200)= $3100`
`text(Income required to make $1500 profit)`
`= 3100 + 1500= $4600`
`:.\ text(Price per ticket)= 4600/200= $23`
Fiona and John are planning to hold a fund-raising event for cancer research. They can hire a function room for $650 and a band for $850. Drinks will cost them $25 per person.
--- 1 WORK AREA LINES (style=lined) ---
--- 1 WORK AREA LINES (style=lined) ---
--- 2 WORK AREA LINES (style=lined) ---
a. `$C = 1500 + 25x`
b. `60`
c. `$500`
a. `text{Fixed Costs} = 650 + 850= $1500`
`text(Variable C) text(osts) = $25x`
`:.\ $C = 1500 + 25x`
| b. | `text(From the graph)` |
| `text(C) text(osts = Income when)\ x = 60` | |
| `text{(i.e. where graphs intersect)}` |
c. `text(When)\ \ x = 80:`
`text(Income)= 80 xx 50$4000`
`$C= 1500 + 25 xx 80= $3500`
`:.\ text(Profit)= 4000-3500= $500`
A clubhouse uses four long-life light globes for five hours every night of the year. The purchase price of each light globe is $6.00 and they each cost `$d` per hour to run.
--- 4 WORK AREA LINES (style=lined) ---
--- 2 WORK AREA LINES (style=lined) ---
--- 2 WORK AREA LINES (style=lined) ---
What is the mean life, in hours, of these light globes if 97.5% will last up to 5000 hours? (1 mark)
--- 2 WORK AREA LINES (style=lined) ---
a. `$c = 24 + 7300d`
b. `0.031\ $ text(/hr)\ text{(3 d.p.)}`
c. `text(Proof)\ \ text{(See Worked Solutions)}`
d. `text(4660 hours.)`
a. `text(Purchase price) = 4 xx 6 = $24`
| `text(Running cost)` | `= text(# Hours) xx text(Cost per hour)` |
| `= 4 xx 5 xx 365 xx d= 7300d` |
`:.\ $c = 24 + 7300d`
b. `text(Given)\ \ $c = $250:`
| `250` | `= 24 + 7300d` |
| `7300d` | `= 226` |
| `d` | `= 226/7300= 0.03095…= 0.031\ $ text(/hr)\ text{(3 d.p.)}` |
c. `text(If)\ d\ text(doubles to 0.062)\ \ $text(/hr)`
`$c= 24 + 7300 xx 0.062= $476.60`
`text(S) text(ince $476.60 is less than)\ 2 xx $250\ ($500),`
`text(the total cost increases to less than double)`
`text(the original cost.)`
d. `sigma = 170`
`z\ text(-score of 5000 hours) = 2`
| `z` | `= (x-mu)/sigma` |
| `2` | `= (5000-mu)/170` |
| `340` | `= 5000-mu` |
| `mu` | `= 4660` |
`:.\ text(The mean life of these globes is 4660 hours.)`
A function centre hosts events for up to 500 people. The cost `C`, in dollars, for the centre
to host an event, where `x` people attend, is given by:
`C = 10\ 000 + 50x`
The centre charges $100 per person. Its income `I`, in dollars, is given by:
`I = 100x`
How much greater is the income of the function centre when 500 people attend an event, than its income at the breakeven point?
`C`
`text(When)\ x=500,\ I=100xx500=$50\ 000`
`text(Breakeven when)\ \ x=200\ \ \ text{(from graph)}`
`text(When)\ \ x=200,\ I=100xx200=$20\ 000`
`text(Difference)=50\ 000-20\ 000=$30\ 000`
`=> C`