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Algebra, STD2 A4 2024 HSC 14 MC

Year 11 is making pizzas to raise money for a charity.

The cost \((C)\) and revenue \((R)\) in dollars, when \(x\) pizzas are sold are represented by the equations

\begin{aligned}
& C=2.5 x+6 \\
& R=8 x 
\end{aligned}

Enough pizzas are sold so that a profit is made.

By how much does the profit increase for each additional pizza sold?

  1. $2.50
  2. $5.50
  3. $6.00
  4. $8.00
Show Answers Only

\(B\)

Show Worked Solution

\(\text {Cost increases by } \$ 2.50 \text { for each extra pizza.}\)

\(\text {Revenue increases by } \$ 8 \text { for each extra pizza.}\)

\(\text {Profit (additional) }=8-2.5=\$ 5.50 \text { per pizza}\)

\(\Rightarrow B\)

♦ Mean mark 49%.

Filed Under: Simultaneous Equations and Applications, Simultaneous Linear Equations Tagged With: Band 5, smc-6920-10-Cost/Revenue, smc-794-10-Cost/Revenue

Algebra, STD2 A4 2019 HSC 36

A small business makes and sells bird houses.

Technology was used to draw straight-line graphs to represent the cost of making the bird houses `(C)` and the revenue from selling bird houses `(R)`. The `x`-axis displays the number of bird houses and the `y`-axis displays the cost/revenue in dollars.
 


 

  1. How many bird houses need to sold to break even?  (1 mark)

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  2. By first forming equations for cost `(C)` and revenue `(R)`, determine how many bird houses need to be sold to earn a profit of $1900.  (3 marks)

    --- 6 WORK AREA LINES (style=lined) ---

Show Answers Only
  1. `20`
  2. `96`
Show Worked Solution

a.   `20\ \ (xtext(-value at intersection))`

 

b.   `text(Find equations of both lines):`

♦♦ Mean mark 28%.

`(0, 500)\ text(and)\ (20, 800)\ text(lie on)\ \ C`

`m_C = (800-500)/(20-0) = 15`

`=> C = 500 + 15x`
 

`(0,0)\ text(and)\ (20, 800)\ text(lie on)\ \ R`

`m_R = (800-0)/(20-0) = 40`

`=> R = 40x`
 

`text(Profit) = R-C`

`text(Find)\ \ x\ \ text(when Profit = $1900:)`

`1900` `= 40x-(500 + 15x)`
`25x` `= 2400`
`x` `= 96`

Filed Under: Simultaneous Equations and Applications, Simultaneous Linear Equations Tagged With: Band 3, Band 5, smc-6920-10-Cost/Revenue, smc-794-10-Cost/Revenue

Algebra, STD2 A4 2018 HSC 27d

The graph displays the cost (`$c`) charged by two companies for the hire of a minibus for `x` hours.
 


  

Both companies charge $360 for the hire of a minibus for 3 hours.

  1. What is the hourly rate charged by Company A?   (1 mark)

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  2. Company B charges an initial booking fee of $75.

     

    Write a formula, in the form of  `c = mx + b`, for the cost of hiring a minibus from Company B for `x` hours.   (2 marks)

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  3. A minibus is hired for 5 hours from Company B.

     

    Calculate how much cheaper this is than hiring from Company A.   (2 marks)

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Show Answers Only

a.    `$120`

b.    `c = 95x + 75`

c.    `$50`

Show Worked Solution

a.    `text(Hourly rate)\ (A)= 360 ÷ 3= $120`

    
b. 
   `m = text(hourly rate)`

`text(Find)\ m,\ text(given)\ c = 360,\ text(when)\ \ x = 3\ \ text(and)\ \ b = 75`

`360` `= m xx 3 + 75`
`3m` `= 285`
`m` `= 95`

 
`:. c = 95x + 75`
 

c.     `text(C)text(ost)\ (A)` `= 120 xx 5 = $600`
  `text(C)text(ost)\ (B)` `= 95 xx 5 + 75 = $550`

 
`:.\ text(The hiring cost for Company)\ B\ text(is $50 cheaper.)`

Filed Under: A3 Types of Relationships (Y12), Simultaneous Equations and Applications, Simultaneous Linear Equations, Simultaneous Linear Equations Tagged With: Band 3, Band 4, smc-1099-10-Cost/Revenue, smc-6839-10-Cost/Revenue, smc-6920-10-Cost/Revenue, smc-794-10-Cost/Revenue

Algebra, STD2 A4 EQ-Bank 27

Penny is a baker and makes meat pies every day.

The cost of making `p` pies, `$C`, can be calculated using the equation

`C = 675 + 3.5 p`

Penny sells the pies for $5.75 each, and her income is calculated using the equation

`I = 5.75 p`

  1. On the graph, draw the graphs of `C` and `I`.   (2 marks)

    --- 0 WORK AREA LINES (style=lined) ---

  2. On the graph, label the breakeven point and the loss zone.   (2 marks)

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Show Answers Only

a. & b.

Show Worked Solution
a.    

 

b.    `text(Loss zone occurs when)\ C > I,\ text(which is shaded in the diagram above.)`

Filed Under: A3 Types of Relationships (Y12), Simultaneous Equations and Applications, Simultaneous Linear Equations, Simultaneous Linear Equations Tagged With: Band 4, Band 5, smc-1099-10-Cost/Revenue, smc-6839-10-Cost/Revenue, smc-6920-10-Cost/Revenue, smc-794-10-Cost/Revenue

Algebra, STD2 A4 2015 HSC 28f

A charity seeks to raise money by telephoning people at random from a call centre and asking them to donate.

Over the years, this charity has found that the amount of money raised `($A)` is related to the number of telephone calls made `(n)`. A graph of this relationship is shown.
 


 

It costs the charity $2100 per week to run the call centre. It also costs an average of 50 cents per telephone call.

  1. Write an equation to represent the total cost,  `C`, of running the call centre for a week in which  `n` phone calls are made.   (1 mark)

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  2. By graphing this equation on the axes above, determine the number of phone calls the charity needs to make in order to break even.   (2 marks)

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Show Answers Only

a.    `C = $2100 + $0.50n`

b.    `text(700 calls)`

Show Worked Solution

a.   `C = $2100 + $0.50n`

♦ Mean marks of 48% and 32% for parts (a) and (b) respectively.

 

b.    

2UG 2015 28f Answer

`text(From the above graph, the charity needs to)`

`text(make 700 calls to break even.)`

Filed Under: Breakeven and Financial modelling, Simultaneous Equations and Applications, Simultaneous Linear Equations Tagged With: Band 5, smc-6920-10-Cost/Revenue, smc-794-10-Cost/Revenue

Algebra, STD2 A4 2005 HSC 28b

Sue and Mikey are planning a fund-raising dance. They can hire a hall for $400 and a band for $300. Refreshments will cost them $12 per person.

  1. Write a formula for the cost ($C) of running the dance for `x` people.   (1 mark)

    --- 2 WORK AREA LINES (style=lined) ---

The graph shows planned income and costs when the ticket price is $20. 

2005 28b

  1. Estimate the minimum number of people needed at the dance to cover the costs.   (1 mark)

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  2. How much profit will be made if 150 people attend the dance?   (1 mark)

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Sue and Mikey plan to sell 200 tickets. They want to make a profit of $1500.

  1. What should be the price of a ticket, assuming all 200 tickets will be sold?   (3 marks)

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Show Answers Only

a.    `700 + 12x`

b.    `text(Approximately 90)`

c.    `$500`

d.    `$23`

Show Worked Solution

a.    `$C= 400 + 300 + (12 xx x)= 700 + 12x`
 

b.    `text(Using the graph intersection:)`

`text(Approximately 90 people are needed to cover the costs.)`
 

c.    `text(If 150 people attend)`

`text(Income)= 150 xx $20= $3000`

`text(C)text(osts)= 700 + (12 xx 150)= $2500`

`:.\ text(Profit)= 3000-2500= $500`
 

d.    `text(C)text(osts when)\ x = 200:`

`C=700 + (12 xx 200)= $3100`

`text(Income required to make $1500 profit)`

`= 3100 + 1500= $4600`
 

`:.\ text(Price per ticket)= 4600/200= $23`

Filed Under: A3 Types of Relationships (Y12), Breakeven and Financial modelling, FM1 - Earning money, Linear Functions, Linear Functions, Simultaneous Equations and Applications, Simultaneous Linear Equations, Simultaneous Linear Equations Tagged With: Band 4, Band 5, common-content, smc-1099-10-Cost/Revenue, smc-6214-55-Cost/Revenue, smc-6839-10-Cost/Revenue, smc-6920-10-Cost/Revenue, smc-794-10-Cost/Revenue, smc-985-10-Cost/Revenue

Algebra, STD2 A4 EQ-Bank 20

Fiona and John are planning to hold a fund-raising event for cancer research.  They can hire a function room for $650 and a band for $850.  Drinks will cost them $25 per person.

  1. Write a formula for the cost ($C) of holding the charity event for `x` people.   (1 mark)

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  2. The graph below shows the planned income and costs if they charge $50 per ticket.  Estimate the number of guests they need to break even.   (1 mark)

     

    --- 1 WORK AREA LINES (style=lined) ---

  3. How much profit will Fiona and John make if 80 people attend their event?   (1 mark)

    --- 2 WORK AREA LINES (style=lined) ---

Show Answers Only

a.    `$C = 1500 + 25x`

b.    `60`

c.    `$500`

Show Worked Solution

a.    `text{Fixed Costs} = 650 + 850= $1500`

 `text(Variable C) text(osts) = $25x`

`:.\ $C = 1500 + 25x`
 

b.   `text(From the graph)`
  `text(C) text(osts = Income when)\ x = 60`
  `text{(i.e. where graphs intersect)}`

 

c.  `text(When)\ \ x = 80:`

`text(Income)= 80 xx 50$4000`

`$C= 1500 + 25 xx 80= $3500`

`:.\ text(Profit)= 4000-3500= $500`

Filed Under: Breakeven and Financial modelling, Linear Functions, Linear Functions, Simultaneous Equations and Applications, Simultaneous Linear Equations Tagged With: Band 4, smc-6214-55-Cost/Revenue, smc-6920-10-Cost/Revenue, smc-794-10-Cost/Revenue, smc-985-10-Cost/Revenue

Algebra, STD2 A4 2011 HSC 20 MC

A function centre hosts events for up to 500 people. The cost `C`, in dollars, for the centre
to host an event, where `x` people attend, is given by:

`C = 10\ 000 + 50x`

The centre charges $100 per person. Its income `I`, in dollars, is given by:

`I = 100x`
 

2UG 2011 20

How much greater is the income of the function centre when 500 people attend an event, than its income at the breakeven point?

  1. `$15\ 000`
  2. `$20\ 000`
  3. `$30\ 000` 
  4. `$40\ 000`
Show Answers Only

`C`

Show Worked Solution
♦ Mean mark 50%
COMMENT: Students can read the income levels directly off the graph to save time and then check with the equations given.

`text(When)\ x=500,\ I=100xx500=$50\ 000`

`text(Breakeven when)\ \ x=200\ \ \ text{(from graph)}`

`text(When)\ \ x=200,\ I=100xx200=$20\ 000`

`text(Difference)=50\ 000-20\ 000=$30\ 000`

`=> C`

Filed Under: A3 Types of Relationships (Y12), Breakeven and Financial modelling, Linear Functions, Linear Functions, Simultaneous Equations and Applications, Simultaneous Linear Equations, Simultaneous Linear Equations Tagged With: Band 5, common-content, smc-1099-10-Cost/Revenue, smc-6214-55-Cost/Revenue, smc-6839-10-Cost/Revenue, smc-6920-10-Cost/Revenue, smc-794-10-Cost/Revenue, smc-985-10-Cost/Revenue

Algebra, STD2 A4 2010 HSC 24b

Ashley makes picture frames as part of her business. To calculate the cost,  `C`, in dollars, of making  `x`  frames, she uses the equation  `C=40+10x`.

She sells the frames for $20 each and determines her income,  `I`, in dollars, using the equation  `I=20x`.
 

Use the graph to solve the two equations simultaneously for  `x`  and explain the significance of this solution for Ashley's business.   (2 marks)

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Show Answers Only

`x=4`

Show Worked Solution

`text(From the graph, intersection occurs at)\ x=4`

♦ Mean mark 36%.
MARKER’S COMMENT: The intersection on the graph is the same point at which the two simultaneous equations are solved for the given value of `x`.

`=>\ text(Break-even point occurs at)\ x=4`

`text(i.e. when 4 frames sold)`

`text(Income)` `=20xx4=$80\ \ text(is equal to)`
`text(C)text(osts)` `=40+(10xx4)=$80`

 

`text(If)\ <4\ text(frames sold)=>\ text(LOSS for business)`

`text(If)\ >4\ text(frames sold)=>\ text(PROFIT)`

Filed Under: A3 Types of Relationships (Y12), Breakeven and Financial modelling, Simultaneous Equations and Applications, Simultaneous Linear Equations, Simultaneous Linear Equations Tagged With: Band 5, smc-1099-10-Cost/Revenue, smc-6839-10-Cost/Revenue, smc-6920-10-Cost/Revenue, smc-794-10-Cost/Revenue

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