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Calculus, 2ADV C4 2022 HSC 29

  1. The diagram shows the graph of  `y=2^{-x}`. Also shown on the diagram are the first 5 of an infinite number of rectangular strips of width 1 unit and height  `y=2^{-x}`  for non-negative integer values of `x`. For example, the second rectangle shown has width 1 and height `(1)/(2)`. 
     

  1. The sum of the areas of the rectangles forms a geometric series.
  2. Show that the limiting sum of this series is 2. (1 mark)

    --- 2 WORK AREA LINES (style=lined) ---

  3. Show that `int_(0)^(4)2^(-x)\ dx=(15)/(16 ln 2)`.   (2 marks)

    --- 5 WORK AREA LINES (style=lined) ---

  4. Use parts (a) and (b) to show that  `e^(15) < 2^(32)`.   (2 marks)

    --- 4 WORK AREA LINES (style=lined) ---

Show Answers Only

a.    `text{Proof (See Worked Solutions)}`

b.    `text{Proof (See Worked Solutions)}`

c.    `text{Proof (See Worked Solutions)}`

Show Worked Solution

a.   `text{Consider the rectangle heights:}`

`2^0=1, \ 2^(-1)=1/2, \ 2^(-2)= 1/4, \ 2^(-3)= 1/8, …`

`=>\ text{Rectangle Areas}\ = 1, \ 1/2, \  1/4, \ 1/8, …`

`a=1,\ \ r=1/2`

`S_oo=a/(1-r)=1/(1-1/2)=2\ \ text{… as required}`
 

b.   `text{Show}\ \ int_0^4 2^(-x)\ dx = 15/(16ln2)`

`int_0^4 2^(-x)\ dx ` `=(-1)/ln2[2^(-x)]_0^4`  
  `=(-1)/ln2(1/16-1)`  
  `=1/ln2-1/(16ln2)`  
  `=(16-1)/(16ln2)`  
  `=15/(16ln2)\ \ text{… as required}`  

 


Mean mark (b) 56%.

c.   `text{Show}\ \ e^15<2^32`

`text{Area under curve < Sum of rectangle areas}`

`15/(16ln2)` `<2`  
`15` `<32ln2`  
`15/32` `<ln2`  
`e^(15/32)` `<e^(ln2)`  
`root(32)(e^15)` `<2`  
`e^15` `<2^32\ \ text{… as required}`  

♦♦♦ Mean mark (c) 9%.

Filed Under: L&E Integration, L&E Integration, Trapezium Rule and Newton, Trapezoidal Rule, Trapezoidal Rule Tagged With: Band 4, Band 6, smc-1203-20-Exponential (Definite), smc-5145-04-Trapezium rule, smc-5145-30-Estimate comparison, smc-7132-20-3+ Applications, smc-7132-30-Estimate vs Actual, smc-7187-20-Exponential (Definite), smc-965-40-Definite Integrals, smc-976-30-Estimate Comparison

Calculus, 2ADV C4 2018 HSC 11e

Evaluate  `int_0^3 e^(5x)\ dx`.  (2 marks)

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`1/5(e^15 – 1)`

Show Worked Solution
`int_0^3 e^(5x)\ dx` `= [1/5 e^(5x)]_0^3`
  `= 1/5 e^15 – 1/5 e^0`
  `= 1/5(e^15 – 1)`

Filed Under: Exponential Calculus, Exponential Calculus (Y12), L&E Integration, L&E Integration Tagged With: Band 3, smc-1203-20-Exponential (Definite), smc-7187-20-Exponential (Definite), smc-965-40-Definite Integrals

Calculus, 2ADV C4 2004 HSC 3bi

Evaluate  `int_1^2 e^(3x)\ dx`.   (2 marks)

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`1/3 (e^6 – e^3)`

Show Worked Solution
  `int_1^2 e^(3x)\ dx` `= 1/3 [e^(3x)]_1^2`
    `= 1/3 (e^6 – e^3)`

Filed Under: Exponential Calculus, Exponential Calculus (Y12), L&E Integration, L&E Integration, Log Calculus Tagged With: Band 3, smc-1203-20-Exponential (Definite), smc-7187-20-Exponential (Definite), smc-965-40-Definite Integrals

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