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Financial Maths, STD2 F5 2013 23 MC

Zina opened an account to save for a new car. Six months after opening the account, she made first deposit of $1200 and continued depositing $1200 at the end of each six month period. Interest was paid at 3% per annum, compounded half-yearly.

How much was in Zina's account two years after first opening it?

  1. $4909.08
  2. $4982.72
  3. $5018.16
  4. $5094.55
Show Answers Only

`A`

Show Worked Solution

`text(Interest: 3% p.a ⇒ 1.5% per 6 months)`

♦ Mean mark 41%.

`text(After 2 years,)`

`text(Value of 1st deposit) = 1200(1.015)^3 = 1254.81`

`text(Value of 2nd deposit) = 1200(1.015)^2 = 1236.27`

`text(Value of 3rd deposit) = 1200(1.015) = 1218`

`text(Value of 4th deposit) = 1200`
 

`:.\ text(Amount in account after 2 years)`

`= 1254.81 + 1236.27 + 1218 + 1200`

`=$4909.08`

`=> A`

Filed Under: F5 Annuities (Y12), Modelling Investments and Loans (Y12) Tagged With: Band 5, common-content, smc-1002-20-FV Formula, smc-816-40-No Table

Statistics, STD2 S1 2018 HSC 17 MC

The area chart shows the number of students involved in tennis or cricket at a school over a number of years.
 


 

In which year was the number of students involved in tennis equal to the number of students involved in cricket?

  1. 2013
  2. 2014
  3. 2015
  4. 2016
Show Answers Only

`C`

Show Worked Solution

`text(Area Charts are cumulative,)`

`text(Consider 2015,)`

`text(Cricket players = 30)`

`text(Tennis players) = 60 – 30 = 30`

`=> C`

Filed Under: Bar Charts, Histograms and Other Graphs (Std 1), Other Chart Types (Y12), Other Charts (Std 2) Tagged With: Band 4, common-content, smc-1128-28-Other Charts, smc-822-40-Other Charts, smc-998-40-Other Charts

Financial Maths, STD2 F4 2008 HSC 24c

Heidi’s funds in a superannuation scheme have a future value of  $740 000  in 20 years time. The interest rate is 4% per annum and earnings are calculated six-monthly.

What single amount could be invested now to produce the same result over the same period of time at the same interest rate?  (3 marks)

Show Answers Only

`$335\ 138.91`

Show Worked Solution
`FV` `= PV(1 + r)^n`
`740\ 000` `= PV(1 + 2/100)^40`
`:. PV` `= (740\ 000)/((1.02)^40)`
  `= 335\ 138.907…`
  `= $335\ 138.91`

Filed Under: Compound Interest and Shares (Std2), F2 Investment (Y12), Modelling Investments and Loans (Y12) Tagged With: Band 4, common-content, smc-1002-20-FV Formula, smc-1108-20-FV Formula, smc-817-20-FV Formula

Measurement, STD2 M6 SM-Bank 2 MC

Which of the following expresses S25°E as a true bearing?

  1.  `025°`
  2.  `065°`
  3.  `115°`
  4.  `155°`
Show Answers Only

`D`

Show Worked Solution

`text(S60°W)` `= 180-25`
  `= 155°`

 
`=>D`

Filed Under: Bearings (Adv-2027), Bearings (Y11), Bearings and Radial Surveys (Std2) Tagged With: Band 4, common-content, smc-6395-30-Compass vs True Bearings, smc-803-30-Compass vs True Bearings, smc-981-20-Compass vs True Bearings

Functions, 2ADV F1 SM-Bank 24

Ita publishes and sells calendars for $25 each. The cost of producing the calendars is $8 each plus a set up cost of $5950.

How many calendars does Ita need to sell to breakeven?  (2 marks)

--- 5 WORK AREA LINES (style=lined) ---

Show Answers Only

`350`

Show Worked Solution

`text(Let)\ \ x =\ text(number of calendars sold)`

`text(C)text(ost) = 5950 + 8x`

`text(Sales revenue) = 25x`
  

`text(Breakeven occurs when:)`

`25x` `= 5950 + 8x`
`17x` `= 5950`
`:. x` `= 350`

Filed Under: Linear Functions (Adv-2027), Linear Functions (Y11) Tagged With: Band 3, common-content, smc-6214-10-Cost/Revenue, smc-985-10-Cost/Revenue

Functions, 2ADV F1 EQ-Bank 22

Worker A picks a bucket of blueberries in `a` hours. Worker B picks a bucket of blueberries in `b` hours.

  1.  Write an algebraic expression for the fraction of a bucket of blueberries that could be picked in one hour if A and B worked together.  (2 marks)

    --- 3 WORK AREA LINES (style=lined) ---

  2.  What does the reciprocal of this fraction represent?  (1 mark)

    --- 2 WORK AREA LINES (style=lined) ---

Show Answers Only
  1. `(a + b)/(ab)`
  2. `text(The reciprocal represents the number of hours it would)`
  3. `text(take to fill one bucket, with A and B working together.)`
Show Worked Solution

i.    `text(In one hour:)`

COMMENT: Note that the question asks for “a fraction”.

`text(Worker A picks)\ 1/a\ text(bucket.)`

`text(Worker B picks)\ 1/b\ text(bucket.)`
 

`:.\ text(Fraction picked in 1 hour working together)`

`= 1/a + 1/b`

`= (a + b)/(ab)`
 

ii.   `text(The reciprocal represents the number of hours it would)`

`text(take to fill one bucket, with A and B working together.)`

Filed Under: Algebraic Techniques (Adv-2027), Algebraic Techniques (Y11) Tagged With: Band 3, Band 4, common-content, smc-6213-10-Algebraic Fractions, smc-983-40-Algebraic Fractions

Functions, 2ADV F1 EQ-Bank 21

Simplify  `(p/q)^3 ÷ (pq^(-2))`.   (2 marks)

Show Answers Only

`(p^2)/q`

Show Worked Solution
`(p/q)^3 ÷ (pq^(-2))` `= (p^3)/(q^3) ÷ p/(q^2)`
  `= (p^3)/(q^3) xx (q^2)/p`
  `= (p^2)/q`

Filed Under: Algebraic Techniques (Adv-2027), Algebraic Techniques (Y11) Tagged With: Band 4, common-content, smc-6213-10-Algebraic Fractions, smc-983-40-Algebraic Fractions

Measurement, STD2 M6 2011 HSC 24c

A ship sails 6 km from `A` to `B` on a bearing of 121°. It then sails 9 km to `C`.  The
size of angle `ABC` is 114°.
 

  1. What is the bearing of `C` from `B`?   (1 mark)

    --- 2 WORK AREA LINES (style=lined) ---

  2. Find the distance `AC`. Give your answer correct to the nearest kilometre.   (2 marks)

    --- 4 WORK AREA LINES (style=lined) ---

  3. What is the bearing of `A` from `C`? Give your answer correct to the nearest degree.   (3 marks)

    --- 6 WORK AREA LINES (style=lined) ---

Show Answers Only
  1.  `055^@`
  2.  `13\ text(km)`
  3.  `261^@`
Show Worked Solution
STRATEGY: Important: Draw North-South parallel lines through major points to make the angle calculations easier!
i.     2011 HSC 24c

 `text(Let point)\ D\ text(be due North of point)\ B`

`/_ABD=180-121\ text{(cointerior with}\ \ /_A text{)}\ =59^@`

`/_DBC=114-59=55^@`   

`:. text(Bearing of)\ \ C\ \ text(from)\ \ B\ \ text(is)\ 055^@`

 

ii.    `text(Using cosine rule:)`

`AC^2` `=AB^2+BC^2-2xxABxxBCxxcos/_ABC`
  `=6^2+9^2-2xx6xx9xxcos114^@`
  `=160.9275…`
`:.AC` `=12.685…\ \ \ text{(Noting}\ AC>0 text{)}`
  `=13\ text(km)\ text{(nearest km)}`

 

iii.    `text(Need to find)\ /_ACB\ \ \ text{(see diagram)}`

MARKER’S COMMENT: The best responses clearly showed what steps were taken with working on the diagram. Note that all North/South lines are parallel.
`cos/_ACB` `=(AC^2+BC^2-AB^2)/(2xxACxxBC)`
  `=((12.685…)^2+9^2-6^2)/(2xx(12.685..)xx9)`
  `=0.9018…`
`/_ACB` `=25.6^@\ text{(to 1 d.p.)}`

 

`text(From diagram,)`

`/_BCE=55^@\ text{(alternate angle,}\ DB\ text(||)\ CE text{)}`

`:.\ text(Bearing of)\ A\ text(from)\ C`

  `=180+55+25.6`
  `=260.6`
  `=261^@\ text{(nearest degree)}`

Filed Under: Bearings and Radial Surveys (Std2) Tagged With: Band 4, Band 5, Band 6, common-content, smc-803-10-Bearings

Trigonometry, 2ADV* T1 2009 HSC 27b

A yacht race follows the triangular course shown in the diagram. The course from  `P`  to  `Q`  is 1.8 km on a true bearing of 058°.

At  `Q`  the course changes direction. The course from  `Q`  to  `R`  is 2.7 km and  `/_PQR = 74^@`.
 

 2009-2UG-27b
 

  1. What is the bearing of  `R`  from  `Q`?   (1 mark)

    --- 2 WORK AREA LINES (style=lined) ---

  2. What is the distance from  `R`  to  `P`?     (2 marks)

    --- 5 WORK AREA LINES (style=lined) ---

  3. The area inside this triangular course is set as a ‘no-go’ zone for other boats while the race is on.

     

    What is the area of this ‘no-go’ zone?   (1 mark)

    --- 2 WORK AREA LINES (style=lined) ---

Show Answers Only
  1. `312^@`
  2. `2.8\ text(km)\ \ \ text{(1 d.p.)}`
  3. `2.3\ text(km²)\ \ \ text{(1 d.p.)}`
Show Worked Solution
i.    2UG-2009-27b-Answer

`/_ PQS = 58^@ \ \ \ (text(alternate to)\ /_TPQ)`

TIP: Draw North-South parallel lines through relevant points to help calculate angles as shown in the Worked Solutions.

`text(Bearing of)\ R\ text(from)\ Q`

`= 180^@ + 58^@ + 74^@`
`= 312^@`

 

(ii)   `text(Using Cosine rule:)`

`RP^2` `=RQ^2` + `PQ^2` `- 2` `xx RQ` `xx PQ` `xx cos` `/_RQP`
  `= 2.7^2` + `1.8^2` `- 2` `xx 2.7` `xx 1.8` `xx cos74^@`
  `=7.29 + 3.24\ – 2.679…`
  `=7.851…`
`:.RP` `= sqrt(7.851…)`
  `=2.8019…`
  `~~ 2.8\ text(km)  (text(1 d.p.) )`

 

(iii)   `text(Using)\ A = 1/2 ab sinC`

`A` `= 1/2` `xx 2.7` `xx 1.8` `xx sin74^@`
  `= 2.3358…`
  `= 2.3\ text(km²)`

 

`:.\ text(No-go zone is 2.3 km²)`

Filed Under: Bearings (Adv-2027), Bearings (Y11) Tagged With: Band 4, Band 5, common-content, smc-6395-10-Bearings, smc-6395-50-Find Area, smc-981-10-Bearings, smc-981-30-Find Area

Trigonometry, 2ADV* T1 2010 HSC 10 MC

A plane flies on a bearing of 150° from  `A`  to  `B`.
 

Capture3

 
What is the bearing of  `A` from `B`?

  1. `30^@`
  2. `150^@`
  3. `210^@`
  4. `330^@`
Show Answers Only

`D`

Show Worked Solution

Capture3-i

`/_TBA=30^@\ \ \ text{(angle sum of triangle)}`

`:.\ text(Bearing of)\ A\ text{from}\ B`

`=360-30`

`=330^@`

`=>  D`

Filed Under: Bearings (Adv-2027), Bearings (Y11) Tagged With: Band 4, common-content, smc-6395-10-Bearings, smc-981-10-Bearings

Trigonometry, 2ADV* T1 2016 HSC 25 MC

The diagram shows towns `A`, `B` and `C`. Town `B` is 40 km due north of town `A`. The distance from `B` to `C` is 18 km and the bearing of `C` from `A` is 025°. It is known that  `∠BCA`  is obtuse.
 

2ug-2016-hsc-25-mc

 
What is the bearing of `C` from `B`?

  1. `070°`
  2. `095°`
  3. `110°`
  4. `135°`
Show Answers Only

`=> D`

Show Worked Solution

`text(Using the sine rule,)`

`(sin∠BCA)/40` `= (sin25^@)/18`
`sin angle BCA` `= (40 xx sin25^@)/18`
  `= 0.939…`
`angle BCA` `= 180 – 69.9quad(angleBCA > 90^@)`
  `= 110.1°`

 

`:. text(Bearing of)\ C\ text(from)\ B`

`= 110.1 + 25qquad(text(external angle of triangle))`

`= 135.1`

`=> D`

Filed Under: Bearings (Adv-2027), Bearings (Y11) Tagged With: Band 4, common-content, smc-6395-10-Bearings, smc-981-10-Bearings

Trigonometry, 2ADV* T1 2014 HSC 23 MC

The following information is given about the locations of three towns `X`, `Y` and `Z`: 
 

• `X` is due east of  `Z`

• `X` is on a bearing of  `145^@`  from  `Y` 

• `Y` is on a bearing of  `060^@`  from  `Z`. 

 
Which diagram best represents this information?
 

HSC 2014 23mci

Show Answers Only

`C`

Show Worked Solution
COMMENT: Drawing a parallel North/South line through `Y` makes this question much simpler to solve.

`text(S)text(ince)\ X\ text(is due east of)\ Z`

`=> text(Cannot be)\ B\ text(or)\ D`
 

 
`text(The diagram shows we can find)`

`/_ZYX = 60 + 35^@ = 95^@`
 

`text(Using alternate angles)\ (60^@)\ text(and)`

`text(the)\ 145^@\ text(bearing of)\ X\ text(from)\ Y`

`=>  C`

Filed Under: Bearings (Adv-2027), Bearings (Y11) Tagged With: Band 4, common-content, smc-6395-10-Bearings, smc-981-10-Bearings

Trigonometry, 2ADV* T1 2008 HSC 17 MC

The diagram shows the position of  `Q`,  `R`  and  `T`  relative to  `P`.
 

VCAA 2008 17 mc

 
In the diagram,

`Q`  is south-west of  `P`

`R`  is north-west  of  `P`

`/_QPT`  is 165°
 

What is the bearing of  `T`  from  `P`?

  1. `060^@`
  2. `075^@`
  3. `105^@` 
  4. `120^@`
Show Answers Only

`A`

Show Worked Solution

VCAA 2008 17 mci

`/_QPS=45^@\ \ \ text{(} Q\ text(is south west of)\ Ptext{)}`

`/_TPS = 165 – 45 = 120^@`

`:.\ /_NPT = 60^@\ \ text{(} 180^@\ text(in straight line) text{)}`

`=>  A`

Filed Under: Bearings (Adv-2027), Bearings (Y11) Tagged With: Band 4, common-content, smc-6395-10-Bearings, smc-981-10-Bearings

Trigonometry, 2ADV* T1 2012 HSC 20 MC

Town `B` is 80 km due north of Town `A` and 59 km from Town `C`.

Town `A` is 31 km from Town `C`.
 

2012 20 mc
 

 What is the bearing of Town `C` from Town `B`?  

  1. `019^@`
  2. `122^@` 
  3. `161^@` 
  4. `341^@` 
Show Answers Only

`C`

Show Worked Solution

`text(Using the cosine rule:)`

`cos\ /_B` `= (a^2 + c^2 -b^2)/(2ac)`
  `= (59^2 + 80^2 -31^2)/(2 xx 59 xx 80)`
  `= 0.9449…`
`/_B` `= 19^@\  text((nearest degree))`

 

`:.\ text(Bearing of Town C from B) = 180-19= 161^@`

`=>  C`

Filed Under: Bearings (Adv-2027), Bearings (Y11) Tagged With: Band 4, common-content, smc-6395-10-Bearings, smc-981-10-Bearings

Trigonometry, 2ADV T1 2018 HSC 12a

A ship travels from Port A on a bearing of 050° for 320 km to Port B. It then travels on a bearing of 120° for 190 km to Port C.
 


 

  1. What is the size of  `/_ ABC`?  (1 mark)

    --- 3 WORK AREA LINES (style=lined) ---

  2. What is the distance from Port A to Port C ? Answer to the nearest 10 kilometres.  (2 marks)

    --- 5 WORK AREA LINES (style=lined) ---

Show Answers Only
  1. `110^@`
  2. `420\ text(km)`
Show Worked Solution
i.  

`text(Let)\ \ D\ \ text(be south of)\ \ B`

`/_ ABD = 50^@ qquad text{(alternate angles)}`

`/_DBC = 60^@ qquad text{(180° in straight line)}`

`:. /_ ABC` `= 50 + 60`
  `= 110^@`

 

ii.  `text(Using the cosine rule:)`

`AC^2` `= AB^2 + BC^2 – 2 *AB*BC* cos /_ ABC`
  `= 320^2 + 190^2 – 2 xx 320 xx 190 xx cos 110^@`
  `= 180\ 089.64…`
`:. AC` `= 424.36…`
  `= 420\ text{km (nearest 10 km)}`

Filed Under: Bearings (Adv-2027), Bearings (Y11), Sine and Cosine Rules, Bearings Tagged With: Band 3, common-content, smc-6395-10-Bearings, smc-981-10-Bearings

Algebra, STD2 A1 2018 HSC 28b

Solve the equation  `(2x)/5 + 1 = (3x + 1)/2`, leaving your answer as a fraction.  (3 marks)

--- 6 WORK AREA LINES (style=lined) ---

Show Answers Only

`5/11`

Show Worked Solution

♦ Mean mark 35%.

`underbrace{(2x)/5 + 1}_text(multiply x10)` `=underbrace{(3x + 1)/2}_text(multiply x10)`
`4x + 10` `= 15x + 5`
`11x` `= 5`
`x` `= 5/11`

Filed Under: Algebraic Fractions, Substitution and Other Equations (Std 1), Substitution and Other Equations (Std 2), Substitution and Other Equations (Std2-2027) Tagged With: Band 5, common-content, num-title-ct-pathc, num-title-qs-hsc, smc-1116-30-Algebraic Fractions, smc-4402-40-Multiple fractions, smc-6234-30-Algebraic Fractions, smc-789-30-Algebraic Fractions

Statistics, STD2 S5 2018 HSC 27e

Joanna sits a Physics test and a Biology test.

  1. Joanna’s mark in the Physics test is 70. The mean mark for this test is 58 and the standard deviation is 8.

     

    Calculate the `z`-score for Joanna’s mark in this test.  (1 mark)

    --- 2 WORK AREA LINES (style=lined) ---

  2. In the Biology test, the mean mark is 64 and the standard deviation is 10.

     

    Joanna’s `z`-score is the same in both the Physics test and the Biology test.

     

    What is her mark in the Biology test?  (2 marks)

    --- 4 WORK AREA LINES (style=lined) ---

Show Answers Only
  1. `1.5`
  2. `79`
Show Worked Solution

i.   `x = 70, \ mu = 58, \ sigma = 8`

`:. ztext(-score)` `= (x – mu)/sigma`
  `= (70 – 58)/8`
  `= 1.5`

 

ii.    `1.5` `= (x – 64)/10`
  `x – 64` `= 15`
  `:. x` `= 79`

Filed Under: Normal Distribution (Y12), S5 The Normal Distribution (Y12) Tagged With: Band 3, Band 4, common-content, smc-819-10-Single z-score, smc-819-30-Comparisons of Data Sets, smc-995-10-Single z-score, smc-995-30-Comparisons of Data Sets

Statistics, STD2 S1 2018 HSC 26e

A cumulative frequency table for a data set is shown.

\begin{array} {|c|c|}
\hline
\ \ \ \ \ \ \ \textit{Score}\ \ \ \ \ \ \   & \ \ \ \ \ \textit{Cumulative}\ \ \ \ \  \\ & \textit{frequency} \\
\hline
\rule{0pt}{2.5ex} \text{1} \rule[-1ex]{0pt}{0pt} & 5 \\
\hline
\rule{0pt}{2.5ex} \text{2} \rule[-1ex]{0pt}{0pt} & 9 \\
\hline
\rule{0pt}{2.5ex} \text{3} \rule[-1ex]{0pt}{0pt} & 16 \\
\hline
\rule{0pt}{2.5ex} \text{4} \rule[-1ex]{0pt}{0pt} & 20 \\
\hline
\rule{0pt}{2.5ex} \text{5} \rule[-1ex]{0pt}{0pt} & 34 \\
\hline
\rule{0pt}{2.5ex} \text{6} \rule[-1ex]{0pt}{0pt} & 42 \\
\hline
\end{array}

What is the interquartile range of this data set?   (2 marks)

--- 4 WORK AREA LINES (style=lined) ---

Show Answers Only

`2`

Show Worked Solution

`text(42 data points ⇒ median) = text(21st + 22nd)/2`

♦♦ Mean mark 27%.

`text(Q)_1` `= 11text(th data point) = 3`
`text(Q)_3` `= 32text(nd data point) = 5`

 

`:.\ text(IQR)` `= 5 – 3`
  `= 2`

Filed Under: Measures of Centre and Spread (Std2-2027), Summary Statistics - No Graph (Std 2), Summary Statistics - No graph (Y12), Summary Statistics (Std 1) Tagged With: Band 5, common-content, smc-1131-30-IQR and Outliers, smc-1131-60-Frequency Tables, smc-6312-30-IQR and Outliers, smc-6312-60-Frequency Tables, smc-824-30-IQR and Outliers, smc-824-60-Frequency Tables, smc-999-30-IQR and Outliers, smc-999-60-Frequency Tables

Statistics, STD2 S1 2018 HSC 26d

The graph displays the mean monthly rainfall in Sydney and Perth.
 


 

  1. For how many months is the mean monthly rainfall higher in Perth than in Sydney?  (1 mark)

    --- 1 WORK AREA LINES (style=lined) ---

  2. For which of the two cities is the standard deviation of the mean monthly rainfall smaller? Justify your answer WITHOUT calculations.  (1 mark)

    --- 2 WORK AREA LINES (style=lined) ---

Show Answers Only
  1. `3`
  2. `text(The mean monthly rainfall of Sydney is in a)`
    `text(much tighter range than Perth.)`
    `:.\ text(Sydney has a smaller standard deviation.)`
Show Worked Solution

i.   `text(3 months (Jul, Aug and Sep))`

♦ Mean mark part (ii) 38%.
COMMENT: Extremely volatile result between parts with part (i) producing a 91% mean mark.

 

ii.    `text(The mean monthly rainfall of Sydney is in a)`

`text(much tighter range than Perth.)`

`:.\ text(Sydney has a smaller standard deviation.)`

Filed Under: Bar Charts and Histograms (Std 2), Bar Charts and Histograms (Std2-2027), Bar Charts and Histograms (Y12), Bar Charts, Histograms and Other Graphs (Std 1) Tagged With: Band 2, Band 5, common-content, smc-1128-10-Bar Charts, smc-6310-10-Bar Charts, smc-821-10-Bar Charts, smc-997-10-Bar Charts

Financial Maths, STD2 F5 2018 HSC 26c

Ali made monthly deposits of $100 into an annuity for 5 years.

Calculate the total amount Ali deposited into the annuity over this period.  (1 mark)

Show Answers Only

`$6000`

Show Worked Solution
`text(Total deposited)` `= 5 xx 12 xx 100`
  `= $6000`

Filed Under: F5 Annuities (Y12), Modelling Investments and Loans (Y12) Tagged With: Band 3, common-content, smc-1002-70-Other Loan/Annuities, smc-816-40-No Table

Probability, STD2 S2 2018 HSC 26a

Jeremy rolled a biased 6-sided die a number of times. He recorded the results in a table.
  

\begin{array} {|l|c|c|c|c|c|c|}
\hline
\rule{0pt}{2.5ex} \text{Number} \rule[-1ex]{0pt}{0pt} & \ \ 1 \ \ & \ \ 2 \ \  & \ \ 3 \ \  & \ \ 4 \ \  & \ \ 5 \ \  & \ \ 6 \ \ \\
\hline
\rule{0pt}{2.5ex} \text{Frequency} \rule[-1ex]{0pt}{0pt} & \ \ 23 \ \ & \ \ 19 \ \  & \ \ 48 \ \  & \ \ 20 \ \  & \ \ 21 \ \  & \ \ 19 \ \ \\
\hline
\end{array} 

What is the relative frequency of rolling a 3?  (1 mark)

--- 2 WORK AREA LINES (style=lined) ---

Show Answers Only

\(\dfrac{8}{25}\)

Show Worked Solution
♦ Mean mark 40%.

\(\text{Rel Freq}\) \(=\dfrac{\text{number of 3’s rolled}}{\text{total rolls}}\)
  \(=\dfrac{48}{150}\)
  \(=\dfrac{8}{25}\)

Filed Under: Probability, Relative Frequency (Std 1), Relative Frequency (Std 2), Relative Frequency (Y11) Tagged With: Band 5, common-content, num-title-ct-core, num-title-qs-hsc, smc-1133-20-Games of Chance, smc-4225-35-Relative frequency, smc-827-20-Games of Chance, smc-990-20-Games of Chance

Functions, 2ADV F1 2018 HSC 3 MC

What is the `x`-intercept of the line  `x + 3y + 6 = 0`?

  1. `(-6, 0)`
  2. `(6, 0)`
  3. `(0, -2)`
  4. `(0, 2)`
Show Answers Only

`A`

Show Worked Solution

`x text(-intercept occurs when)\ y = 0:`

`x + 0 + 6` `= 0`
`x` `= -6`

 
`:. x text{-intercept is}\  (-6, 0)`

`=>  A`

Filed Under: 6. Linear Functions, Cartesian Plane, Linear Equations and Basic Graphs (Std 2), Linear Functions (Adv-2027), Linear Functions (Y11) Tagged With: Band 3, common-content, num-title-ct-pathc, num-title-qs-hsc, smc-4422-80-Other, smc-6214-05-Coordinate Geometry, smc-792-20-Equation of Line, smc-985-30-Coordinate Geometry

Statistics, STD2 S5 2018 HSC 23 MC

A set of data is normally distributed with a mean of 48 and a standard deviation of 3.

Approximately what percentage of the scores lies between 39 and 45?

  1. 15.85%
  2. 31.7%
  3. 47.5%
  4. 49.85%
Show Answers Only

`A`

Show Worked Solution

`text(Given)\ \ mu = 48, \ sigma = 3`

♦ Mean mark 47%.

`ztext{-score (39)}` `= (x – mu)/sigma`
  `= (39 – 48)/3`
  `= −3`

 

`ztext{-score (45)}` `= (45 – 48)/3`
  `= −1`

 

 
`:.\ text(Scores between 39 and 45)`

`~~ 16text(%)`

`=>A`

`text(Note that % of scores below 39 is very small.)`

Filed Under: Normal Distribution (Y12), S5 The Normal Distribution (Y12) Tagged With: Band 5, common-content, smc-819-20-z-score Intervals, smc-995-20-z-score Intervals

Probability, STD2 S2 2018 HSC 20 MC

During a year, the maximum temperature each day was recorded. The results are shown in the table.
  


  

From the days with a maximum temperature less than 25°C, one day is selected at random.

What is the probability, to the nearest percentage, that the selected day occurred during winter?

  1. 19%
  2. 25%
  3. 32%
  4. 77%
Show Answers Only

`text(C)`

Show Worked Solution
`text{P(winter day)}` `= (text(winter days < 25))/text(total days < 25) xx 100`
  `= 71/223 xx 100`
  `= 31.8…%`

`=>\ text(C)`

Filed Under: Probability, Relative Frequency (Std 1), Relative Frequency (Std 2), Relative Frequency (Y11) Tagged With: Band 4, common-content, num-title-ct-core, num-title-qs-hsc, smc-1133-10-Surveys/Two-Way Tables, smc-4225-35-Relative frequency, smc-827-10-Surveys/Two-Way Tables, smc-990-10-Surveys/Two-Way Tables

Financial Maths, STD2 F4 2018 HSC 19 MC

The table shows the compounded values of $1 at different interest rates over different periods.
 

 
Amy hopes to have $21 000 in 2 years to buy a car. She opens an account today which pays interest of 4% pa, compounded quarterly.

Using the table, which expression calculates the minimum single sum that Amy needs to invest today to ensure she reaches her savings goal?

  1. 21 000 × 1.0816
  2. 21 000 ÷ 1.0816
  3. 21 000 × 1.0829
  4. 21 000 ÷ 1.0829
Show Answers Only

`text(D)`

Show Worked Solution

`text(4% annual)`

♦♦ Mean mark 33%.

`=> (4%)/4 = 1text(% compounded quarterly)`

`=> n = 8`

`=>\  text(Factor) = 1.0829`

`:.\ text(Minimum sum) = 21\ 000 ÷ 1.0829`

`=>\ text(D)`

Filed Under: Compound Interest and Shares (Std2), F2 Investment (Y12), Modelling Investments and Loans (Y12) Tagged With: Band 5, common-content, smc-1002-10-Compounded Value of $1 Table, smc-1108-40-Compounded Value of $1, smc-817-10-Compounded Value of $1 Table

Statistics, STD2 S1 2018 HSC 11 MC

A set of data is summarised in this frequency distribution table.
 

 
Which of the following is true about the data?

  1. Mode = 7, median = 5.5
  2. Mode = 7, median = 6
  3. Mode = 9, median = 5.5
  4. Mode = 9, median = 6
Show Answers Only

`text(B)`

Show Worked Solution

`text{Mode = 7  (highest frequency of 9)}`

`text(Median = average of 15th and 16th data points.)`

`:.\ text(Median = 6)`

`=>\ text(B)`

Filed Under: Data Analysis, Measures of Centre and Spread (Std2-2027), Summary Statistics - No Graph (Std 2), Summary Statistics - No graph (Y12), Summary Statistics (Std 1) Tagged With: Band 4, common-content, num-title-ct-core, num-title-qs-hsc, smc-1131-20-Median and Mode, smc-1131-60-Frequency Tables, smc-4224-15-Mode, smc-4224-25-Mean, smc-6312-20-Median and Mode, smc-6312-60-Frequency Tables, smc-824-20-Median and Mode, smc-824-60-Frequency Tables, smc-999-20-Median and Mode, smc-999-60-Frequency Tables

Measurement, STD2 M6 2018 HSC 7 MC

The diagram shows the positions of towns `A`, `B` and `C`.

Town `A` is due north of town `B` and `angleCAB = 34°`
  


 

What is the bearing of town `C` from town `A`?

  1. 034°
  2. 146°
  3. 214°
  4. 326°
Show Answers Only

`C`

Show Worked Solution

`text(Bearing of Town)\ C\ text(from Town)\ A:`
 

`text(Bearing)` `= 180 + 34`
  `= 214^@`

 
`=>C`

Filed Under: Bearings and Radial Surveys (Std2), M3 Right-Angled Triangles (Y12) Tagged With: Band 4, common-content, smc-1103-60-Bearings, smc-803-10-Bearings

Statistics, STD2 S1 2018 HSC 6 MC

A set of data is displayed in this dot plot.
 


 

Which of the following best describes this set of data?

  1. Symmetrical
  2. Positively skewed
  3. Negatively skewed
  4. Normally distributed
Show Answers Only

`text(C)`

Show Worked Solution

`text(Data is skewed.)`

♦ Mean mark 43% (a surprisingly poor result!)

`text(S)text(ince the “tail” is on the left had side, the)`

`text(data is negatively skewed.)`

`=>\ text(C)`

Filed Under: Other Chart Types (Y12), Other Charts (Std 2), Other Charts (Std2-2027) Tagged With: Band 5, common-content, smc-6311-30-Other Charts, smc-822-40-Other Charts, smc-998-40-Other Charts

Statistics, STD2 S1 2018 HSC 3 MC

A survey asked the following question.

'How many brothers do you have?'

How would the responses be classified?

  1. Categorical, ordinal
  2. Categorical, nominal
  3. Numerical, discrete
  4. Numerical, continuous
Show Answers Only

`text(C)`

Show Worked Solution

`text(The number of brothers a person has is)`

`text(an exact whole number.)`

`:.\ text(Classification is numerical, discrete.)`

`=>\ text(C)`

Filed Under: Classifying Data, Classifying Data (Std 1), Classifying Data (Std 2), Classifying Data (Y12), Data Classification, Investigation and Sampling Methods (Std2-2027) Tagged With: Band 4, common-content, num-title-ct-core, num-title-qs-hsc, smc-1127-20-Classifying Data, smc-5075-15-Numerical, smc-6309-20-Data Classification, smc-820-20-Classifying Data

Statistics, STD2 S1 2018 HSC 1 MC

A set of scores has the following five-number summary.

lower extreme = 2
lower quartile = 5
median = 6
upper quartile = 8
upper extreme = 9

What is the range?

  1. 2
  2. 3
  3. 6
  4. 7
Show Answers Only

`text(D)`

Show Worked Solution
`text(Range)` `=\ text(upper extreme − lower extreme)`
  `= 9 – 2`
  `= 7`

`=>\ text(D)`

Filed Under: Measures of Centre and Spread (Std2-2027), Summary Statistics - No Graph (Std 2), Summary Statistics - No graph (Y12), Summary Statistics (Std 1) Tagged With: Band 3, common-content, smc-1131-70-Other, smc-6312-70-Other, smc-824-70-Other, smc-999-70-Other

Functions, 2ADV F1 2017 HSC 1 MC

What is the gradient of the line  `2x + 3y + 4 = 0`?

  1. `-2/3`
  2. `2/3`
  3. `-3/2`
  4. `3/2`
Show Answers Only

`A`

Show Worked Solution
`2x + 3y + 4` `= 0`
`3y` `= -2x-4`
`y` `= -2/3 x-4/3`
`:.\ text(Gradient)` `= -2/3`

 
`=>  A`

Filed Under: 6. Linear Functions, Cartesian Plane, Linear Equations and Basic Graphs (Std 2), Linear Functions (Adv-2027), Linear Functions (Y11) Tagged With: Band 3, common-content, num-title-ct-pathc, num-title-qs-hsc, smc-4422-20-Gradient, smc-4422-50-General form, smc-6214-05-Coordinate Geometry, smc-792-10-Gradient, smc-985-30-Coordinate Geometry

Measurement, STD2 M6 2017 HSC 30c

The diagram shows the location of three schools. School `A` is 5 km due north of school `B`, school `C` is 13 km from school `B` and `angleABC` is 135°.
 


 

  1. Calculate the shortest distance from school `A` to school `C`, to the nearest kilometre.  (2 marks)

    --- 4 WORK AREA LINES (style=lined) ---

  2. Determine the bearing of school `C` from school `A`, to the nearest degree.  (3 marks)

    --- 6 WORK AREA LINES (style=lined) ---

Show Answers Only
  1. `17\ text{km  (nearest km)}`
  2. `213^@`
Show Worked Solution

i.   `text(Using cosine rule:)`

`AC^2` `= AB^2 + BC^2 – 2 xx AB xx BC xx cos135^@`
  `= 5^2 + 13^2 – 2 xx 5 xx 13 xx cos135^@`
  `= 285.923…`
`:. AC` `= 16.909…`
  `= 17\ text{km  (nearest km)}`

 

ii.   

`text(Using sine rule, find)\ angleBAC:`

♦♦ Mean mark 31%.
`(sin angleBAC)/13` `= (sin 135^@)/17`
`sin angleBAC` `= (13 xx sin 135^@)/17`
  `= 0.5407…`
`angleBAC` `= 32.7^@`

 

`:. text(Bearing of)\ C\ text(from)\ A`

`= 180 + 32.7`

`= 212.7^@`

`= 213^@`

Filed Under: Bearings & Field Surveys, Bearings and Radial Surveys (Std2) Tagged With: Band 5, common-content, smc-803-10-Bearings

Statistics, STD2 S1 2017 HSC 30a

A set of data has a lower quartile (`Q_L`) of 10 and an upper quartile (`Q_U`) of 16.

What is the maximum possible range for this set of data if there are no outliers?  (2 marks)

--- 4 WORK AREA LINES (style=lined) ---

Show Answers Only

`24`

Show Worked Solution

`IQR = 16 – 10 = 6`

♦♦ Mean mark 34%.

`text(If no outliers,)`

`text(Upper limit)` `= Q_U + 1.5 xx IQR`
  `= 16 + 1.5 xx 6`
  `= 25`
`text(Lower limit)` `= Q_L – 1.5 xx IQR`
  `= 10 – 1.5 xx 6`
  `= 1`

 

`:.\ text(Maximum range)` `= 25 – 1`
  `= 24`

Filed Under: Measures of Centre and Spread (Std2-2027), Summary Statistics - No Graph (Std 2), Summary Statistics - No graph (Y12), Summary Statistics (no graph), Summary Statistics (Std 1) Tagged With: Band 5, common-content, smc-1131-30-IQR and Outliers, smc-6312-30-IQR and Outliers, smc-824-30-IQR and Outliers, smc-999-30-IQR and Outliers

Statistics, STD2 S5 2017 HSC 29d

All the students in a class of 30 did a test.

The marks, out of 10, are shown in the dot plot.
 


 

  1. Find the median test mark.  (1 mark)

    --- 1 WORK AREA LINES (style=lined) ---

  2. The mean test mark is 5.4. The standard deviation of the test marks is 4.22.

     

    Using the dot plot, calculate the percentage of the marks which lie within one standard deviation of the mean.  (2 marks)

    --- 4 WORK AREA LINES (style=lined) ---

  3. A student states that for any data set, 68% of the scores should lie within one standard deviation of the mean. With reference to the dot plot, explain why the student’s statement is NOT relevant in this context.  (1 mark)

    --- 2 WORK AREA LINES (style=lined) ---

Show Answers Only
  1. `6`
  2. `text(43%)`
  3. `text(The statement assumes the data is normally)`
    `text(distributed which is not the case here.)`
Show Worked Solution
♦ Mean mark 50%.
i.    `text(Median)` `= text(15th + 16th score)/2`
    `= (4 + 8)/2`
    `= 6`

 

ii.   `text(Lower limit) = 5.4 – 4.22 = 1.18`

♦♦ Mean mark 34%.

`text(Upper limit) = 5.4 + 4.22 = 9.62`

`:.\ text(Percentage in between)`

`= 13/30 xx 100`

`= 43.33…`

`= 43text{%  (nearest %)}`

 

iii.   `text(The statement assumes the data is normally)`

♦♦♦ Mean mark 13%.

`text(distributed which is not the case here.)`

Filed Under: DS5/6 - Normal Distribution and Sampling, Normal Distribution (Y12), S5 The Normal Distribution (Y12) Tagged With: Band 3, Band 5, Band 6, common-content, smc-819-20-z-score Intervals, smc-819-30-Comparisons of Data Sets, smc-995-20-z-score Intervals, smc-995-30-Comparisons of Data Sets

Probability, STD2 S2 2017 HSC 29c

A group of Year 12 students was surveyed. The students were asked whether they live in the city or the country. They were also asked if they have ever waterskied.

The results are recorded in the table.
  


  

  1. A person is selected at random from the group surveyed. Calculate the probability that the person lives in the city and has never waterskied.  (2 marks)

    --- 4 WORK AREA LINES (style=lined) ---

  2. A newspaper article claimed that Year 12 students who live in the country are more likely to have waterskied than those who live in the city.

     

    Is this true, based on the survey results? Justify your answer with relevant calculations.  (2 marks)

    --- 4 WORK AREA LINES (style=lined) ---

Show Answers Only
  1. `125/176`
  2. `text(See Worked Solutions)`
Show Worked Solution
i.     `P` `= text(live in city, not skied)/text(total surveyed)`
    `= 2500/3520`
    `= 125/176`
♦ Mean mark part (ii) 47%.

 

ii.   `P(text(live in country, skied))` `= 70/((70 + 800))`
    `= 0.0804…`
    `= 8text(%)`

 

`P(text(live in city, skied))` `= 150/((150 + 2500))`
  `= 0.0566`
  `= 6text(%)`

 
`text(S)text(ince 8% > 6%, the statement is true.)`

Filed Under: Relative Frequency, Relative Frequency (Std 1), Relative Frequency (Std 2), Relative Frequency (Y11) Tagged With: Band 4, Band 5, common-content, smc-1133-10-Surveys/Two-Way Tables, smc-827-10-Surveys/Two-Way Tables, smc-990-10-Surveys/Two-Way Tables

Financial Maths, STD2 F5 2017 HSC 27c

A table of future value interest factors for an annuity of $1 is shown.
 


 

An annuity involves contributions of $12 000 per annum for 5 years. The interest rate is 4% per annum, compounded annually.

  1. Calculate the future value of this annuity.  (1 mark)

    --- 1 WORK AREA LINES (style=lined) ---

  2. Calculate the interest earned on this annuity.  (1 mark)

    --- 1 WORK AREA LINES (style=lined) ---

Show Answers Only
  1. `$64\ 995.60`
  2. `$4995.60`
Show Worked Solution

i.   `text(FV factor = 5.4163)`

`:.\ text(FV of Annuity)` `= 12\ 000 xx 5.4163`
  `= $64\ 995.60`
♦♦ Mean mark part (ii) 22%.
COMMENT: A very poorly answered question dealing with a core concept in this area.

 

ii.   `text(Interest earned)` `=\ text(FV − total repayments)`
    `= 64\ 995.60 – (5 xx 12\ 000)`
    `= $4995.60`

Filed Under: F5 Annuities (Y12), FM5 - Annuities and Loan repayments, Modelling Investments and Loans (Y12) Tagged With: Band 4, Band 5, common-content, smc-1002-40-FV Annuity Table, smc-816-10-FV of $1 Annuity Table

Statistics, STD2 S1 2017 HSC 27a

Jamal surveyed eight households in his street. He asked them how many kilolitres (kL) of water they used in the last year. Here are the results.

`220, 105, 101, 450, 37, 338, 151, 205`

  1. Calculate the mean of this set of data.  (1 mark)

    --- 1 WORK AREA LINES (style=lined) ---

  2. What is the standard deviation of this set of data, correct to one decimal place?  (1 mark)

    --- 1 WORK AREA LINES (style=lined) ---

Show Answers Only
  1. `200.875`
  2. `127.4\ \ text{(1 d.p.)}`
Show Worked Solution
i.   `text(Mean)` `= (220 + 105 + 101 + 450 + 37 + 338 + 151 + 205) ÷ 8`
    `= 200.875`
♦ Mean mark part (ii) 47%.
IMPORTANT: The population standard deviation is required here.

 

ii.   `text(Std Dev)` `= 127.357…\ \ text{(by calc)}`
    `= 127.4\ \ text{(1 d.p.)}`

Filed Under: Measures of Centre and Spread (Std2-2027), Standard Deviation, Summary Statistics - No Graph (Std 2), Summary Statistics - No graph (Y12), Summary Statistics (no graph), Summary Statistics (Std 1) Tagged With: Band 3, Band 5, common-content, num-title-ct-corea, num-title-qs-hsc, smc-1131-10-Mean, smc-1131-50-Std Dev (by calc), smc-5020-10-By calculator, smc-6312-10-Mean, smc-6312-50-Std Dev (by Calc), smc-824-10-Mean, smc-824-50-Std Dev (by calc), smc-999-50-Std Dev (by calc)

Statistics, STD2 S5 2017 HSC 13 MC

The heights of Year 12 girls are normally distributed with a mean of 165 cm and a standard deviation of 5.5 cm.

What is the `z`-score for a height of 154 cm?

A.     `−2`

B.    `−0.5`

C.     `0.5`

D.     `2`

Show Answers Only

`text(A)`

Show Worked Solution
`ztext(-score)` `= (x – mu)/sigma`
  `= (154 – 165)/5.5`
  `= −2`

 
`=>A`

Filed Under: DS5/6 - Normal Distribution and Sampling, Normal Distribution (Y12), S5 The Normal Distribution (Y12) Tagged With: Band 3, common-content, smc-819-10-Single z-score, smc-995-10-Single z-score

Statistics, STD2 S4 2017 HSC 12 MC

Which of the data sets graphed below has the largest positive correlation coefficient value?
 

A.      B.     
C.      D.     
Show Answers Only

\(C\)

Show Worked Solution

\(\text{Largest positive correlation occurs when both variables move}\)

\(\text{in tandem. The tighter the linear relationship, the higher the}\)

\(\text{correlation.}\)

\(\Rightarrow C\)

\(\text{(Note that B is negatively correlated)}\)

Filed Under: Bivariate Data, Bivariate Data Analysis (Y12), Correlation / Body Measurements, S3 Further Statistical Analysis (Y12), S4 Bivariate Data Analysis (Y12) Tagged With: Band 3, common-content, num-title-ct-coreb, num-title-qs-hsc, smc-1001-30-Correlation, smc-1113-30-Correlation, smc-5022-30-Correlation, smc-785-30-Correlation

Financial Maths, STD2 F4 2017 HSC 10 MC

A single amount of $10 000 is invested for 4 years, earning interest at the rate of 3% per annum, compounded monthly.

Which expression will give the future value of the investment?

  1. `10\ 000 xx (1 + 0.03)^4`
  2. `10\ 000 xx (1 + 0.03)^48`
  3. `10\ 000 xx (1 + 0.03/12)^4`
  4. `10\ 000 xx (1 + 0.03/12)^48`
Show Answers Only

`D`

Show Worked Solution

`text(Compounding rate)\ = 3/100 ÷ 12= 0.03/12`

`text(Compounding periods)` `= 4 xx 12=48`

 
`:.\ text(FV) = 10\ 000 xx (1 + 0.03/12)^48`

\(\Rightarrow D\)

Filed Under: Compound Interest and Shares (Std2), F2 Investment (Y12), FM2 - Investing, Modelling Investments and Loans (Y12) Tagged With: Band 4, common-content, smc-1002-20-FV Formula, smc-1108-20-FV Formula, smc-817-20-FV Formula

Algebra, STD2 A1 2017 HSC 9 MC

What is the value of  `x`  in the equation  `(5-x)/3 = 6`?

  1. `-13`
  2. `-3`
  3. `3`
  4. `13`
Show Answers Only

`A`

Show Worked Solution
`(5-x)/3` `= 6`
`5-x` `= 18`
`x` `= 5-18`
  `= -13`

`=>A`

Filed Under: Algebraic Fractions, Linear and Other Equations, Substitution and Other Equations (Std 1), Substitution and Other Equations (Std 2), Substitution and Other Equations (Std2-2027) Tagged With: Band 3, common-content, num-title-ct-corea, num-title-qs-hsc, smc-1116-30-Algebraic Fractions, smc-4402-10-Single fraction, smc-6234-30-Algebraic Fractions, smc-789-30-Algebraic Fractions

Statistics, STD2 S1 2017 HSC 4 MC

A factory’s quality control department has tested every 50th item produced for possible defects.

What type of sampling has been used?

A.     Random

B.     Stratified

C.     Systematic

D.     Numerical

Show Answers Only

`C`

Show Worked Solution

`text(A systematic sample divides a population)`

`text(into equal sample sizes and then selects)`

`text(equally among them.)`

`=> C`

Filed Under: Classifying Data (Std 1), Classifying Data (Std 2), Data Classification, Investigation and Sampling Methods (Std2-2027), DS1 - Stats and society Tagged With: Band 4, common-content, smc-1127-10-Sampling Methods, smc-6309-10-Sampling Methods, smc-820-10-Sampling Methods

Probability, STD2 S2 2017 HSC 5 MC

In a survey of 200 randomly selected Year 12 students it was found that 180 use social media.

Based on this survey, approximately how many of 75 000 Year 12 students would be expected to use social media?

A.     60 000

B.     67 500

C.     74 980

D.     75 000

Show Answers Only

`B`

Show Worked Solution
`text(Expected number)` `= 180/200 xx 75\ 000`
  `= 67\ 500`

`=> B`

Filed Under: DS5/6 - Normal Distribution and Sampling, Probability, Relative Frequency, Relative Frequency (Std 1), Relative Frequency (Std 2), Relative Frequency (Y11) Tagged With: Band 3, common-content, num-title-ct-core, num-title-qs-hsc, smc-1133-10-Surveys/Two-Way Tables, smc-1133-30-Expected Frequency (np), smc-4225-35-Relative frequency, smc-827-10-Surveys/Two-Way Tables, smc-827-40-Expected Frequency (np), smc-990-10-Surveys/Two-Way Tables, smc-990-40-Expected Frequency (np)

Algebra, STD2 A2 2017 HSC 3 MC

The graph shows the relationship between infant mortality rate (deaths per 1000 live births) and life expectancy at birth (in years) for different countries.
 

What is the life expectancy at birth in a country which has an infant mortality rate of 60?

  1. 68 years
  2. 69 years
  3. 86 years
  4. 88 years
Show Answers Only

\(A\)

Show Worked Solution

\(\text{When infant mortality rate is 60, life expectancy}\)

\(\text{at birth is 68 years (see below).}\)
 

\(\Rightarrow A\)

Filed Under: Applications: Currency, Fuel and Other Problems (Std 1), Applications: Currency, Fuel and Other Problems (Std 2), Applications: Currency, Fuel and Other Problems (Std2-2027), Bivariate Data, Life Expectancy, Linear Applications, S3 Further Statistical Analysis (Y12), S4 Bivariate Data Analysis (Y12) Tagged With: Band 3, common-content, num-title-ct-coreb, num-title-qs-hsc, smc-1001-10-Line of Best Fit, smc-1113-10-Line of Best Fit, smc-1119-30-Other Linear Applications, smc-5022-10-Line of best fit graphs, smc-6256-30-Other Linear Applications, smc-785-10-Line of Best Fit, smc-793-30-Other Linear Applications

Statistics, STD2 S1 2017 HSC 1 MC

The box-and-whisker plot for a set of data is shown.
 

What is the median of this set of data?

  1. 15
  2. 20
  3. 30
  4. 35
Show Answers Only

`C`

Show Worked Solution

`text(Median = 30)`

`=> C`

Filed Under: Box Plots and 5-Number Summary, Stem & Leaf, Box & Whisker, Summary Statistics - Box Plots (Std 2), Summary Statistics - Box Plots (Std2-2027), Summary Statistics (Std 1) Tagged With: Band 2, common-content, num-title-ct-corea, num-title-qs-hsc, smc-1131-35-Box Plots, smc-5021-18-Find median, smc-5021-50-Box plot (single), smc-6313-10-Single Box Plots, smc-825-10-Single Box-Plots

Algebra, STD2 A2 2016 HSC 29e

The graph shows the life expectancy of people born between 1900 and 2000.
 


  1. According to the graph, what is the life expectancy of a person born in 1932?  (1 mark)

    --- 1 WORK AREA LINES (style=lined) ---

  2. With reference to the value of the gradient, explain the meaning of the gradient in this context.  (2 marks)

    --- 4 WORK AREA LINES (style=lined) ---

Show Answers Only
  1. `text(68 years)`
  2. `text(After 1900, life expectancy increases 0.25 years for each later year someone is born.)`
Show Worked Solution

i.    \(\text{68 years}\)

ii.    \(\text{Using (1900,60), (1980,80):}\)

\(\text{Gradient}\) \(= \dfrac{y_2-y_1}{x_2-x_1}\)
  \(= \dfrac{80-60}{1980-1900}\)
  \(= 0.25\)

 
\(\text{After 1900, life expectancy increases by 0.25 years for}\)

\(\text{each year later that someone is born.}\)

♦♦ Mean mark (ii) 33%.

Filed Under: Applications: Currency, Fuel and Other Problems (Std 1), Applications: Currency, Fuel and Other Problems (Std 2), Applications: Currency, Fuel and Other Problems (Std2-2027), Bivariate Data Analysis (Y12), Life Expectancy, Other Linear Modelling, S3 Further Statistical Analysis (Y12), S4 Bivariate Data Analysis (Y12) Tagged With: Band 3, Band 5, common-content, smc-1001-10-Line of Best Fit, smc-1001-50-Gradient Interpretation, smc-1113-10-Line of Best Fit, smc-1113-50-Gradient, smc-1119-30-Other Linear Applications, smc-6256-30-Other Linear Applications, smc-785-10-Line of Best Fit, smc-785-50-Gradient Interpretation, smc-793-30-Other Linear Applications

Statistics, STD2 S1 2016 HSC 29c

The ages of members of a dance class are shown in the back-to-back stem-and-leaf plot.
 

2ug-2016-hsc-q29_2
 

Pat claims that the women who attend the dance class are generally older than the men.

Is Pat correct? Justify your answer by referring to the median and skewness of the two sets of data.  (3 marks)

--- 6 WORK AREA LINES (style=lined) ---

Show Answers Only

`text(Women:)`

`text(The median is 55 in a data)`

`text(set that is negatively skewed.)`

`text(Men:)`

`text(The median is 45 in a data)`

`text(set that is positively skewed.)`

`:.\ text(Pat is correct.)`

Show Worked Solution

`text(Women:)`

♦ Mean mark 44%.

`text(The median is 55 in a data)`

`text(set that is negatively skewed.)`

`text(Men:)`

`text(The median is 45 in a data)`

`text(set that is positively skewed.)`

`:.\ text(Pat is correct.)`

Filed Under: Bar Charts, Histograms and Other Graphs (Std 1), Other Chart Types (Y12), Other Charts (Std 2), Other Charts (Std2-2027), Stem & Leaf, Box & Whisker Tagged With: Band 5, common-content, smc-1128-26-Back-to-back Stem and Leaf, smc-6311-20-Back-to-Back Stem-and-Leaf, smc-822-30-Back-to-Back Stem and Leaf, smc-998-30-Back-to-Back Stem and Leaf

Algebra, STD2 A4 2016 HSC 29b

The mass `M` kg of a baby pig at age `x` days is given by  `M = A(1.1)^x`  where `A` is a constant. The graph of this equation is shown.
 

2ug-2016-hsc-q29_1

  1. What is the value of `A`?   (1 mark)

    --- 1 WORK AREA LINES (style=lined) ---

  2. What is the daily growth rate of the pig’s mass? Write your answer as a percentage.   (1 mark)

    --- 2 WORK AREA LINES (style=lined) ---

Show Answers Only
  1. `1.5\ text(kg)`
  2. `10text(%)`
Show Worked Solution

i.   `text(When)\ x = 0,`

♦ Mean mark (i) 48%.
♦♦♦ Mean mark part (ii) 6%!

`1.5` `= A(1.1)^0`
`:. A` `= 1.5\ text(kg)`

 
ii.
   `text(Daily growth rate)`

`= 0.1`

`= 10text(%)`

Filed Under: Exponential/Quadratic (Projectile), Graphs and Applications (Y11), Non-Linear: Exponential/Quadratics (Std 2) Tagged With: Band 5, Band 6, common-content, smc-830-30-Exponential, smc-966-10-Exponential graphs, smc-966-30-Other exponential modelling

Financial Maths, STD2 F5 2016 HSC 28d

The table gives the contribution per period for an annuity with a future value of $1 at different interest rates and different periods of time. 
 

2ug-2016-hsc-q28_31
 

Margaret needs to save $75 000 over 6 years for a deposit on a new apartment. She makes regular quarterly contributions into an investment account which pays interest at 3% pa.

How much will Margaret need to contribute each quarter to reach her savings goal?  (2 marks)

--- 4 WORK AREA LINES (style=lined) ---

Show Answers Only

`$2865`

Show Worked Solution

`text(Periods) = 6 xx 4 = 24`

♦ Mean mark 40%.

`text(Interest rate) = 1/4 xx 3 = 0.75text(%)`

`=>\ text(Table factor = 0.0382)`

`(text(i.e. 3.82 cents contributed per)`

  `text(quarter = $1 after 6 years))`

 

`:.\ text(Quarterly contribution)`

`= 75\ 000 xx 0.0382`

`= $2865`

Filed Under: F5 Annuities (Y12), FM5 - Annuities and Loan repayments, Modelling Investments and Loans (Y12) Tagged With: Band 5, common-content, smc-1002-60-Other Annuity Tables, smc-816-30-Other Annuity Tables

Statistics, STD2 S1 2016 HSC 27c

The heights of 400 students were measured. The results are displayed in this cumulative frequency polygon.
 

2ug-2016-hsc-q27_2

 
Use the polygon to estimate the interquartile range.  (2 marks)

--- 4 WORK AREA LINES (style=lined) ---

Show Answers Only

`36\ text(cm)`

Show Worked Solution

`text(See graph for values:)`

♦ Mean mark 46%.

2ug-2016-hsc-q27c-answer

`IQR` `= Q_3 – Q_1`
  `= 172 – 136`
  `= 36\ text(cm)`

Filed Under: Bar Charts and Histograms, Bar Charts and Histograms (Std 2), Bar Charts and Histograms (Std2-2027), Bar Charts and Histograms (Y12), Bar Charts, Histograms and Other Graphs (Std 1) Tagged With: Band 5, common-content, smc-1128-20-Cumulative Frequency Histograms, smc-1128-30-IQR, smc-6310-30-Cumulative Frequency Histograms, smc-6310-40-IQR, smc-821-20-Cumulative Frequency Histograms, smc-821-30-IQR, smc-997-20-Cumulative Frequency Histograms, smc-997-30-IQR

Statistics, STD2 S1 2016 HSC 27b

A small population consists of three students of heights 153 cm, 168 cm and 174 cm. Samples of varying sizes can be taken from this population.

What is the mean of the mean heights of all the possible samples? Justify your answer.  (2 marks)

--- 4 WORK AREA LINES (style=lined) ---

Show Answers Only

`165\ text(cm)`

Show Worked Solution

`text(If sample is 1 person,)`

♦ Mean mark 40%.

`text{Possible mean(s): 153, 168 or 174.}`
 

`text(If sample is 2 people,)`

`text{Possible mean(s):}quad(153 + 168)/2` `= 160.5`
`(153 + 174)/2` `= 163.5`
`(168 + 174)/2` `= 171`

 

`text(If sample is 3 people,)`

`text(Mean:)quad(153 + 168 + 174)/3 = 165`
 

`:.\ text(Mean of all mean heights)`

`= (153 + 168 + 174 + 160.5 + 163.5 + 171 + 165)/7`

`= 165\ text(cm)`

Filed Under: Measures of Centre and Spread (Std2-2027), Summary Statistics - No Graph (Std 2), Summary Statistics - No graph (Y12), Summary Statistics (no graph) Tagged With: Band 5, common-content, smc-6312-10-Mean, smc-824-10-Mean, smc-999-10-Mean

Measurement, STD2 M6 2016 HSC 25 MC

The diagram shows towns `A`, `B` and `C`. Town `B` is 40 km due north of town `A`. The distance from `B` to `C` is 18 km and the bearing of `C` from `A` is 025°. It is known that  `∠BCA`  is obtuse.
 

2ug-2016-hsc-25-mc

 
What is the bearing of `C` from `B`?

  1.    `070°`
  2.    `095°`
  3.    `110°`
  4.    `135°`
Show Answers Only

`=> D`

Show Worked Solution

`text(Using the sine rule,)`

♦ Mean mark 39%.
`(sin∠BCA)/40` `= (sin25^@)/18`
`sin angle BCA` `= (40 xx sin25^@)/18`
  `= 0.939…`
`angle BCA` `= 180 – 69.9quad(angleBCA > 90^@)`
  `= 110.1°`

 

`:. text(Bearing of)\ C\ text(from)\ B`

`= 110.1 + 25qquad(text(external angle of triangle))`

`= 135.1`

 
`=> D`

Filed Under: Bearings & Field Surveys, Bearings and Radial Surveys (Std2) Tagged With: Band 5, common-content, smc-803-10-Bearings

Probability, STD2 S2 2016 HSC 23 MC

A group of 485 people was surveyed. The people were asked whether or not they smoke. The results are recorded in the table.
 

A person is selected at random from the group.

What is the approximate probability that the person selected is a smoker OR is male?

  1. 33%
  2. 18%
  3. 68%
  4. 87%
Show Answers Only

`=> C`

Show Worked Solution

`P(text(Smoker or a male))`

`= (text(Total males + female smokers))/(text(Total surveyed))`

`= (264 + 68)/485`

`= 0.684…`
 

`=> C`

♦♦ Mean mark 34%.

Filed Under: Relative Frequency, Relative Frequency (Std 1), Relative Frequency (Std 2), Relative Frequency (Y11), Relative Frequency and Venn Diagrams Tagged With: Band 6, common-content, num-title-ct-pathb, num-title-qs-hsc, smc-1133-10-Surveys/Two-Way Tables, smc-4815-10-2-Way tables, smc-4815-50-Conditional probability, smc-827-10-Surveys/Two-Way Tables, smc-990-10-Surveys/Two-Way Tables

Statistics, STD2 S1 2016 HSC 22 MC

The box-and-whisker plots show the results of a History test and a Geography test.
 

In History, 112 students completed the test. The number of students who scored above 30 marks was the same for the History test and the Geography test.

How many students completed the Geography test?

  1. 8
  2. 50
  3. 56
  4. 112
Show Answers Only

`=> C`

Show Worked Solution

`text{In History} \ => \  text{Q}_3 = 30\ \text{marks}`

`:.\ text{Scoring over 30}\ = 25text(%) xx 112 = 28\ \text{students}`
 

`text{In Geography} \ => \ text{Median}\ = 30\ \text{marks}`

`:.\ text{Students completing Geography}\ =2 xx 28 = 56\ \text{students}`

`=> C`

Filed Under: Box Plots and 5-Number Summary, Stem & Leaf, Box & Whisker, Summary Statistics - Box Plots (Std 2), Summary Statistics - Box Plots (Std2-2027), Summary Statistics - Box Plots (Y12), Summary Statistics (Std 1) Tagged With: Band 4, common-content, num-title-ct-corea, num-title-qs-hsc, smc-1000-20-Parallel Box-Plots, smc-1131-35-Box Plots, smc-5021-60-Box plots (parallel), smc-6313-20-Parallel Box Plots, smc-825-20-Parallel Box-Plots

Statistics, STD2 S1 2016 HSC 21 MC

A grouped data frequency table is shown.

\begin{array} {|c|c|}
\hline
\rule{0pt}{2.5ex} \textit{Class Interval} \rule[-1ex]{0pt}{0pt} & \ \ \ \ \ \textit{Frequency}\ \ \ \ \  \\
\hline
\rule{0pt}{2.5ex} \text{1 – 5} \rule[-1ex]{0pt}{0pt} & 3 \\
\hline
\rule{0pt}{2.5ex} \text{6 – 10} \rule[-1ex]{0pt}{0pt} & 6 \\
\hline
\rule{0pt}{2.5ex} \text{11 – 15} \rule[-1ex]{0pt}{0pt} & 8 \\
\hline
\rule{0pt}{2.5ex} \text{16 – 20} \rule[-1ex]{0pt}{0pt} & 9 \\
\hline
\end{array}

What is the mean for this set of data?

  1.    6.5
  2.    10.5
  3.    11.9
  4.    12.4
Show Answers Only

`=> D`

Show Worked Solution

`text(Using the centre of each class interval:)`

♦ Mean mark 43%.
`text(Mean)` `= (3 xx 3 + 8 xx 6 + 13 xx 8 + 18 xx 9)/(3 + 6 + 8 + 9)`
  `= 12.42…`

`=> D`

Filed Under: Measures of Centre and Spread (Std2-2027), Summary Statistics - No Graph (Std 2), Summary Statistics - No graph (Y12), Summary Statistics (no graph), Summary Statistics (Std 1) Tagged With: Band 5, common-content, smc-1131-10-Mean, smc-1131-40-Class Centres, smc-6312-10-Mean, smc-6312-40-Class Centres, smc-824-10-Mean, smc-824-40-Class Centres, smc-999-10-Mean, smc-999-40-Class Centres

Statistics, STD2 S1 2016 HSC 19 MC

A soccer referee wrote down the number of goals scored in 9 different games during the season.

`2,  \ 3,  \ 3,  \ 3,  \ 5,  \ 5,  \ 8,  \ 9,  \ ...`

The last number has been omitted. The range of the data is 10.

What is the five-number summary for this data set?

  1. `2, 3, 5, 8.5, 12`
  2. `2, 3, 5, 8.5, 10`
  3. `2, 3, 5, 8, 12`
  4. `2, 3, 5, 8, 10`
Show Answers Only

`=> A`

Show Worked Solution

`text{Since range is 10} \ => \ text{Last data point = 12}`

`text{Q}_1 = 3`

`text{Q}_3 = (8 + 9)/2 = 8.5`

`text(Median = 5)`

`=> A`

♦ Mean mark 46%.

Filed Under: Box Plots and 5-Number Summary, Measures of Centre and Spread (Std2-2027), Stem & Leaf, Box & Whisker, Summary Statistics - Box Plots (Std 2), Summary Statistics - Box Plots (Std2-2027), Summary Statistics - Box Plots (Y12), Summary Statistics - No Graph (Std 2), Summary Statistics (no graph), Summary Statistics (Std 1) Tagged With: Band 5, common-content, num-title-ct-corea, num-title-qs-hsc, smc-1000-10-Single Box-Plots, smc-5021-15-5 number (even values), smc-5021-18-Find median, smc-5021-25-Find range, smc-6312-70-Other, smc-6313-10-Single Box Plots, smc-824-70-Other, smc-825-10-Single Box-Plots

Statistics, STD2 S5 2016 HSC 13 MC

The speed limit outside a school is 40 km/h. Year 11 students measured the speed of passing vehicles over a period of time. They found the set of data to be normally distributed with a mean speed of 36 km/h and a standard deviation of 2 km/h.

What percentage of the vehicles passed the school at a speed greater than 40 km/h?

  1. `text(2.5%)`
  2. `text(5%)`
  3. `text(47.5%)`
  4. `text(95%)`
Show Answers Only

`=> A`

Show Worked Solution
`z` `= (x – mu)/sigma`
  `= (40 – 36)/2`
  `= 2`

2ug-2016-hsc-13-mc-answer

`=> A`

Filed Under: DS5/6 - Normal Distribution and Sampling, Normal Distribution (Y12), S5 The Normal Distribution (Y12) Tagged With: Band 4, common-content, smc-819-10-Single z-score, smc-995-10-Single z-score

Financial Maths, STD2 F4 2016 HSC 8 MC

The table shows the future value of an investment of $1000, compounding yearly, at varying interest rates for different periods of time.
 

2ug-2016-hsc-8-mc 

 
Based on the information provided, what is the future value of an investment of $2500 over 3 years at 4% pa?

  1.    $1124.86
  2.    $2812.15
  3.    $3624.86
  4.    $5312.15
Show Answers Only

`=> B`

Show Worked Solution

`text(Table factor) = 1124.86`

`:. FV` `= 2.5 xx 1124.86`
  `= $2812.15`

 
`=> B`

Filed Under: Compound Interest and Shares (Std2), F2 Investment (Y12), FM2 - Investing, Modelling Investments and Loans (Y12) Tagged With: Band 4, common-content, smc-1002-10-Compounded Value of $1 Table, smc-1108-40-Compounded Value of $1, smc-817-10-Compounded Value of $1 Table

Statistics, STD2 S1 2016 HSC 7 MC

Which set of data is classified as categorical and nominal?

  1. blue, green, yellow
  2. small, medium, large
  3. 5.2 cm, 6 cm, 7.21 cm
  4. 4 people, 5 people, 9 people 
Show Answers Only

`A`

Show Worked Solution

`text(Categorical and nominal data is)`

♦♦ Mean mark 26%.

`text(qualitative and not ordered.)`

`=> A`

Filed Under: Classifying Data, Classifying Data (Std 1), Classifying Data (Std 2), Classifying Data (Y12), Data Classification, Investigation and Sampling Methods (Std2-2027), DS1 - Stats and society Tagged With: Band 6, common-content, num-title-ct-core, num-title-qs-hsc, smc-1127-20-Classifying Data, smc-5075-10-Categorical, smc-6309-20-Data Classification, smc-820-20-Classifying Data

Statistics, STD2 S4 2016 HSC 3 MC

The graph shows a scatterplot for a set of data.
 

2ug-2016-hsc-3-mc 

 
Which of the following is the best approximation for the correlation coefficient of this set of data?

  1.    `−1`
  2.    `−0.3`
  3.    `0.3`
  4.    `1`
Show Answers Only

`B`

Show Worked Solution

`text(Correlation is negative and)`

`text(weak.)`

`=> B`

Filed Under: Bivariate Data Analysis (Y12), Correlation / Body Measurements, S4 Bivariate Data Analysis (Y12) Tagged With: Band 4, common-content, smc-1001-30-Correlation, smc-785-30-Correlation

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